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A 4.0 mm-diameter copper ball is charged to 90 nC. What is the number of electrons removed from the Copper ball?

A 4.0 mm-diameter copper ball is charged to 90 nC. What is the number of electrons removed from the Copper ball?

Solution:

Given that

Diameter of Copper Ball = d = 4.00mm

Charge on Ball = q = 90 nC = 90 x 10-9 C

Charge on an Electron = e =1.6 x 10-19 C

if N is number of electrons removed from the Copper Ball 

N =
Given Charge
Charge on electron

90 x 10-9+19
90 x 10-9
N=
1,6 X 10-19
=
1.6

N=
90 x 10-9+19
90 x 1010
1.6
56.25 x 1010
1.6

N = 56,25 x 1010

this is number of electron remove from Copper 

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